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12th Class Physics Electrostatics & Capacitance Question Bank MCQ - Electrostatic Potential and Capacitance

  • question_answer
    A \[20\mu F\]and a \[10\mu F\]capacitor are connected in series and a potential difference is applied across the combination. The \[20\mu F\]capacitor has:

    A) twice the charge of the \[10\mu F\]capacitor

    B) half the charge of the\[10\mu F\]capacitor

    C) half the potential difference of \[10\mu F\] capacitor

    D) twice the potential difference of \[10\mu F\]capacitor

    Correct Answer: C

    Solution :

    (c) half the potential difference of \[10\mu F\]capacitor \[{{C}_{eq}}=\frac{20\times 10}{20+10}=\frac{200}{30}\mu F\] Charge on each capacitor,\[Q={{C}_{eq}}V=\left( \frac{200}{30}V \right)\] \[{{V}_{1}}=\frac{\frac{200}{30}V}{20}=\frac{V}{3}\Rightarrow {{V}_{2}}=\frac{\frac{200}{30}V}{10}=\frac{2V}{3}\] Hence, \[20\mu F\]capacitor has half the potential difference of \[10\mu F\]capacitor.


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