question_answer

Three capacitors each of capacity \[4\mu F\]are to be connected in such a way that the effective capacitance is \[6\,\mu F\]. This can be done by:

A) connecting them in series

B) connecting them is parallel

C) connecting two in series and one is parallel

D) connecting two in parallel and one in series

Correct Answer: C

Solution :

(c) connecting two in series and one is parallel To get equivalent capacitance \[6\,\mu F\], two \[4\,\mu F\]capacitors are to be connected in series and third one is connected in parallel. From figure equivalent capacitance, \[{{C}_{eq}}\frac{4\times 4}{4+4}+4=2+4=6\mu F\]