A) 500J
B) 250J
C) 125J
D) 1.25J
Correct Answer: D
Solution :
(d) 1.25J Here, \[C=10\,\mu F,\]\[V=500\,V,\,R=10\,\Omega \] Energy stored in capacitor \[=\frac{1}{2}C{{V}^{2}}\] \[=\frac{1}{2}\times 10\times {{10}^{-6}}\times {{\left( 500 \right)}^{2}}\] \[=5\times {{10}^{-6}}\times 25\times {{10}^{4}}\] \[=125\times {{10}^{-2}}=1.25\,J\] Energy stored in capacitor is converted into heat. Hence, heat produced = 1.25 J.You need to login to perform this action.
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