A) 990
B) 900
C) 9090
D) 909
Correct Answer: C
Solution :
(c) 9090 Let n capacitors are connected in parallel, \[{{C}_{parallel}}=nC\] We know that, \[Q={{C}_{parallel}}V\] \[1=\left( nC \right)\times 110\] \[1=n\times 1\mu F\times 110\] \[n=\frac{1}{110\times {{10}^{-6}}}=\frac{{{10}^{6}}}{110}\] \[n=9090\]You need to login to perform this action.
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