A) \[E\left( 2a+2b \right)\]
B) \[E\left( 2a \right)\]
C) Ea
D) zero
Correct Answer: D
Solution :
(d) zero Work done in moving a charge q from o to b = 0 Work done in moving a charge q from c to d = 0 This is because electric field is perpendicular to the displacement. Now, work done from b to c = - work done from d to a \[\therefore \] Total work done = 0You need to login to perform this action.
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