A) 2/3 V
B) 3/2 V
C) 3 V
D) 1/3 V
Correct Answer: A
Solution :
(a) 2/3 V Radius of sphere =1G cm Potential inside sphere is same as on its surface \[\therefore \,\,\,\,\,\,\,\,V=\frac{kq}{10}\] (1) Now, \[V'=\frac{Kq}{15}\] (2) \[\frac{V}{V'}=\frac{kq}{10}\times \frac{15}{Kq}=\frac{3}{2}\] \[\Rightarrow \,\,\,\,\,\,\,\,V'=\frac{2}{3}V\]You need to login to perform this action.
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