A) \[\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{q}{r}\]
B) \[\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{q}{{{r}^{2}}}\]
C) zero
D) \[\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{p}{{{r}^{2}}}\]
Correct Answer: C
Solution :
(c) zero Electric potential at any point in the equatorial plane of a dipole is zero.
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