A) \[25\mu C\]from smaller to bigger
B) \[25\mu C\]from bigger to smaller
C) \[50\mu C\]from smaller to bigger
D) \[50\mu C\]from bigger to smaller
Correct Answer: A
Solution :
(a) \[25\mu C\]from smaller to bigger Here, \[{{r}_{1}}=5\,cm,\,{{r}_{2}}=10\,cm\] \[{{C}_{1}}=75\,\mu C,\,{{C}_{2}}=75\mu C\] At equilibrium, \[{{V}_{1}}={{V}_{2}}\] \[\Rightarrow \frac{K{{q}_{1}}}{{{r}_{1}}}=\frac{K{{q}_{2}}}{{{r}_{2}}}\Rightarrow \frac{{{q}_{1}}}{5}=\frac{{{q}_{2}}}{10}\] \[\Rightarrow {{q}_{2}}=2{{q}_{1}}\] (1) We know that, \[{{q}_{1}}+{{q}_{2}}=75+75\] \[\Rightarrow \,\,\,{{q}_{1}}+2{{q}_{1}}=150\] \[\Rightarrow \,3{{q}_{1}}=150\] \[\Rightarrow \,\,{{q}_{1}}=50\,\,\mu C\] \[\Rightarrow \,\,{{q}_{2}}=2\times 50=100\mu C\] Hence,\[25\mu C\left( 75-50 \right)\]charge is transferred from smaller to bigger.
You need to login to perform this action.
You will be redirected in
3 sec
