A) 2W
B) 3W
C) 4W
D) \[\frac{W}{2}\]
Correct Answer: C
Solution :
(c) 4W Work done in rotating dipole by \[\theta \], \[W=pE\left( 1-\cos \theta \right)\] \[=pE\left( 1-\cos \,60{}^\circ \right)=pE\left( 1-\frac{1}{2} \right)=\frac{1}{2}pE\] \[\Rightarrow pE=2W\] \[W'=pE\left( 1-\cos \,180{}^\circ \right)\] \[W'=2W\left[ 1-\left( -1 \right) \right]\] \[W'=4W\]You need to login to perform this action.
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