A) At a distance d/2 from charge q
B) At a distance d/2 from charge -2q
C) At a distance d/3 from charge q
D) At a distance d/3 from charge -2q
Correct Answer: C
Solution :
(c) At a distance d/3 from charge q Let P be the required point at distance x from charge q. \[\therefore \,\,\,\,\,\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{q}{x}+\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{\left( -2a \right)}{d-x}=0\] \[\frac{1}{x}=\frac{2}{d-x}\] \[d-x=2x\] \[\Rightarrow \,\,x=\frac{d}{3}\] \[\therefore \] Required point is at a distance d/3 from charge q.You need to login to perform this action.
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