A) -1.1 J
B) 2 J
C) 2.5 J
D) 3 J
Correct Answer: A
Solution :
(a) -1.1J Here, \[{{q}_{1}}=4\mu C,\,{{q}_{2}}=-3\mu C,\,r=10cm=0.1\,m\] Electrostatic potential energy, \[U=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{q}_{1}}{{q}_{2}}}{r}\] \[=9\times {{10}^{9}}\times \frac{4\times {{10}^{-6}}\times \left( -3 \right)\times {{10}^{-6}}}{0.1}=-1.1\,J\]
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