A) \[4.5\times {{10}^{-12}}J\]
B) \[5.1\times {{10}^{-8}}J\]
C) \[2.5\times {{10}^{-12}}J\]
D) \[3.2\times {{10}^{-8}}J\]
Correct Answer: B
Solution :
(b) \[5.1\times {{10}^{-8}}J\] Here, \[C=16\,pF\] \[=16\times {{10}^{-12}}f;\,\,V=80\,V\] As \[U=\frac{1}{2}C{{V}^{2}}\] \[=\frac{1}{2}\times 16\times {{10}^{-12}}\times {{\left( 80 \right)}^{2}}\] \[=5.1\times {{10}^{-8}}J\]You need to login to perform this action.
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