A) 1 : 1
B) \[1:{{n}^{2}}\]
C) \[{{n}^{2}}:1\]
D) None of these
Correct Answer: B
Solution :
(b) \[1:{{n}^{2}}\] When n capacitors are connected in series, \[C{{ & }_{series}}=\frac{C}{n}\] When n capacitors are connected in parallel, \[{{C}_{parallel}}=nC\] \[\frac{{{C}_{series}}}{{{C}_{parallel}}}=\frac{C/n}{nC}=\frac{1}{{{n}^{2}}}\]You need to login to perform this action.
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