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12th Class Physics Electrostatics & Capacitance Question Bank MCQ - Electrostatic Potential and Capacitance

  • question_answer
    The distance between the plates of a charged plate capacitor disconnected from the battery is 5 cm and the intensity of the field in it is f = 300 V/cm. An uncharged metal bar 1 cm thick is introduced into the capacitor parallel to its plates. The potential difference between the plates now is:

    A) 1500 V                         

    B) 1200 V   

    C) 900 V                           

    D) zero

    Correct Answer: B

    Solution :

    (b) 1200V Potential, \[V=E\text{ }\times \text{ }d=300\times \left( 5\text{ }-1 \right)\] \[=300\times 4=1200V\]


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