A) \[\frac{36}{13\mu F}\]
B) \[2\mu F\]
C) \[1\mu F\]
D) \[3\mu F\]
Correct Answer: D
Solution :
(d) \[3\mu F\] \[{{C}_{1}}\] and \[{{C}_{2}}\]are in series \[\therefore \,\,\,\,\,\,\,\,\frac{1}{C'}=\frac{1}{{{C}_{1}}}+\frac{1}{{{C}_{2}}}=\frac{1}{3}+\frac{1}{6}\] \[\Rightarrow \,\,\,\,\,C'=2\mu F\] Similarly, \[{{C}_{3}}\] and \[{{C}_{4}}\]are in series \[\frac{1}{C''}=\frac{1}{{{C}_{3}}}+\frac{1}{{{C}_{4}}}=\frac{1}{2}+\frac{1}{2}\] \[\Rightarrow \,\,\,C''=1\mu F\] Now, C and C" are in parallel \[\therefore \,\,\,\,\,\,\,\,\,{{C}_{eq}}=C'+C''=2+1=3\mu F\]You need to login to perform this action.
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