A) twice the charge of the \[10\mu F\]capacitor
B) half the charge of the\[10\mu F\]capacitor
C) half the potential difference of \[10\mu F\] capacitor
D) twice the potential difference of \[10\mu F\]capacitor
Correct Answer: C
Solution :
(c) half the potential difference of \[10\mu F\]capacitor \[{{C}_{eq}}=\frac{20\times 10}{20+10}=\frac{200}{30}\mu F\] Charge on each capacitor,\[Q={{C}_{eq}}V=\left( \frac{200}{30}V \right)\] \[{{V}_{1}}=\frac{\frac{200}{30}V}{20}=\frac{V}{3}\Rightarrow {{V}_{2}}=\frac{\frac{200}{30}V}{10}=\frac{2V}{3}\] Hence, \[20\mu F\]capacitor has half the potential difference of \[10\mu F\]capacitor.You need to login to perform this action.
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