A) \[51.7\,\,J\,{{T}^{-1}}\]
B) \[69.2\,J\,{{T}^{-1}}\]
C) \[38.6\,J\,{{T}^{-1}}\]
D) \[19.5\,J\,{{T}^{-1}}\]
Correct Answer: B
Solution :
(b) \[69.2\,J\,{{T}^{-1}}\] Here, \[~N=100,l=15\,A,r=7cm=7\times {{10}^{-2}}m\] \[\therefore M=NlA=Nl\times \pi {{r}^{2}}\] \[=300\times 15\times 3.14\times {{(7\times {{10}^{-2}})}^{2}}=69.2\,J\,{{T}^{-1}}\]
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