A) \[4.8\times {{10}^{-2}}Nm\]
B) \[1.6\times {{10}^{-2}}Nm\]
C) \[1.2\times {{10}^{-2}}Nm\]
D) \[4.8\times {{10}^{-4}}Nm\]
Correct Answer: A
Solution :
(a) \[4.8\times {{10}^{-2}}Nm\] Torque, \[\tau =MB\,sin\theta \] Here \[M=1.28\text{ }J{{T}^{-1}},\text{ }B=7.5\times {{10}^{-2}}\text{ }T,\text{ }\theta =30{}^\circ \] \[\therefore \tau =1.28\times 7.5\times {{10}^{-2}}sin\,30{}^\circ \] \[=1.28\times 7.5\times {{10}^{-2}}\times \frac{1}{2}\] \[=0.64\times 7.5\times {{10}^{-2}}=4.8\times {{10}^{-2}}Nm\]You need to login to perform this action.
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