A) \[0.3\text{ }G\text{ }and\text{ }\delta =30{}^\circ \]
B) \[0.4\text{ }G\text{ }and\text{ }\delta \text{=}40{}^\circ \]
C) \[0.5\text{ }G\text{ }and\text{ }\delta \text{=5}0{}^\circ \]
D) \[0.6\text{ }G\text{ }and\text{ }\delta \text{=6}0{}^\circ \]
Correct Answer: D
Solution :
(d) \[0.6\text{ }G\text{ }and\text{ }\delta \text{=6}0{}^\circ \] Here, \[{{B}_{H}}=0.3\,\,G,\,\,{{B}_{V}}=0.52\,G\] The Earth's magnetic field, \[B=\sqrt{B_{H}^{2}+B_{V}^{2}}=\sqrt{{{(0.3)}^{2}}+{{(0.52)}^{2}}}=0.6\,G\] and angle of dip, \[\tan \,\delta =\frac{{{B}_{V}}}{{{B}_{H}}}=\frac{0.52}{0.3}=1734\] \[\delta \,={{\tan }^{-1}}(1.734)=60{}^\circ \]
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