12th Class Physics Magnetism Question Bank MCQ - Magnetism and Matter

  • question_answer
    The vertical component of Earth's magnetic field at a place is \[\sqrt{3}\] times the horizontal component, the value of angle of dip at this place is:

    A) \[30{}^\circ \]                          

    B)             \[45{}^\circ \]      

    C)             \[60{}^\circ \]                          

    D)             \[90{}^\circ \]

    Correct Answer: C

    Solution :

    (c) \[60{}^\circ \] As,           \[{{B}_{V}}=\sqrt{3}\,{{B}_{H}}\] Also.                 \[\tan \delta =\frac{{{B}_{V}}}{{{B}_{H}}}=\frac{\sqrt{3}{{B}_{H}}}{{{B}_{H}}}=\sqrt{3}\] or \[\delta ={{\tan }^{-1}}(\sqrt{3})=60{}^\circ \] \[\therefore \]      Angle of dip, \[\delta =60{}^\circ \].


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