12th Class Physics Magnetism Question Bank MCQ - Magnetism and Matter

  • question_answer
                             In the magnetic meridian of a certain place the horizontal component of Earth's magnetic field is 0.25 G and dip angle is \[60{}^\circ \]. The magnetic field of the Earth at this location is:

    A) 0.50 G                         

    B)             0.52 G    

    C)             0.54 G                         

    D)             0.56 G      

    Correct Answer: A

    Solution :

    (a) 0.50 G  Here,     \[{{H}_{E}}=0.25\,G\] and \[\cos \delta =\frac{{{H}_{E}}}{{{B}_{E}}}\] \[\therefore \] The magnetic field of Earth at the given location is                    \[{{B}_{E}}=\frac{{{H}_{E}}}{\cos \,60{}^\circ }=\frac{0.25}{1/2}=0.50\,G\]


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