A) 0.50 G
B) 0.52 G
C) 0.54 G
D) 0.56 G
Correct Answer: A
Solution :
(a) 0.50 G Here, \[{{H}_{E}}=0.25\,G\] and \[\cos \delta =\frac{{{H}_{E}}}{{{B}_{E}}}\] \[\therefore \] The magnetic field of Earth at the given location is \[{{B}_{E}}=\frac{{{H}_{E}}}{\cos \,60{}^\circ }=\frac{0.25}{1/2}=0.50\,G\]You need to login to perform this action.
You will be redirected in
3 sec