A) \[7.78\times {{10}^{5}}A{{m}^{-1}}\]
B) \[8.88\times {{10}^{5}}A{{m}^{-1}}\]
C) \[9.98\times {{10}^{5}}A{{m}^{-1}}\]
D) \[10.2\times {{10}^{5}}A{{m}^{-1}}\]
Correct Answer: C
Solution :
(c) \[9.98\times {{10}^{5}}A{{m}^{-1}}\] As \[B={{\mu }_{0}}(M+H)\] Magnetisation, \[M=\frac{(B-{{\mu }_{0}}H)}{{{\mu }_{0}}}\] Then \[M=\frac{{{\mu }_{0}}{{\mu }_{r}}H-{{\mu }_{0}}H}{{{\mu }_{0}}}=({{\mu }_{r}}-1)H\] \[(\because \,B={{\mu }_{0}}{{\mu }_{r}}H)\] Here, \[{{\mu }_{r}}=500\] and \[H=nl=1000\times 2=200\,A{{m}^{-1}}\] \[\therefore \] \[M=(500-1)H=499\times 2000\] Or \[M=9.98\times {{10}^{5}}A{{m}^{-1}}\]
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