A) 2.24 A
B) 2.34 mA
C) 3.33 A
D) 3.33 mA
Correct Answer: C
Solution :
(c) 3.33 A Here, \[N=900\text{ }turns,\] \[A=2\times {{10}^{-4}}{{m}^{2}},{{M}_{s}}=0.6\,A{{m}^{2}}\] The magnetic moment of solenoid, \[{{M}_{s}}=NlA\] The current flowing through the solenoid is \[l=\frac{{{M}_{s}}}{NA}=\frac{0.6}{900\times 2\times {{10}^{-4}}}=3.33\,A\]You need to login to perform this action.
You will be redirected in
3 sec