A) \[24.9\,\Omega \]
B) \[249\,\Omega \]
C) \[2490\,\Omega \]
D) \[24900\,\Omega \]
Correct Answer: C
Solution :
(c) \[2490\,\Omega \] Here, \[{{l}_{g}}=1mA=1\times {{10}^{-3}}A,\,{{R}_{G}}=10\,\Omega \] \[V=2.5\,V\] From the figure, \[V={{l}_{g}}({{R}_{G}}+R)\] or \[R=\frac{V}{{{l}_{g}}}{{R}_{G}}\] Substituting the given values, we get, \[R=\frac{2.5\,V}{1\times {{10}^{-3}}A}-10\,\Omega =2500\,\Omega -10\,\Omega =2490\,\Omega \]You need to login to perform this action.
You will be redirected in
3 sec