A) 210 mA
B) 155 mA
C) 420 mA
D) 75 mA
Correct Answer: A
Solution :
(a) 210 mA \[{{l}_{g}}=\frac{50}{5}=10\,mA;\,{{R}_{G}}=40\,\Omega ,\,{{r}_{s}}=2\,\Omega \] Maximum current, \[l=\frac{{{R}_{G}}+{{r}_{S}}}{{{r}_{s}}.}\times {{l}_{g}}=\frac{(40+2)\times 10}{2}=210\,mA\]You need to login to perform this action.
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