2. Questions Bank
  3. 12th Class
  4. Physics
  5. Magnetism

12th Class Physics Magnetism Question Bank MCQ - Moving Charges and Magnetism

  • question_answer
    A A deuteron of kinetic energy 50 keV is describing a circular orbit of radius 0.5 m in a plane perpendicular to the magnetic field \[\overrightarrow{B}\]. The kinetic energy of the proton that describes a circular orbit of same radius and inside same \[\overrightarrow{B}\] is:

    A) 25 keV                         

    B) 50 keV

    C) 200 keV                        

    D) 100 keV       

    Correct Answer: D

    Solution :

    (d) 100 keV                                                      \[KE=\frac{{{q}^{2}}{{B}^{2}}{{r}^{2}}}{2m}\] \[\Rightarrow KE\propto \frac{1}{m}\Rightarrow KE=100\,keV\]


You need to login to perform this action.
You will be redirected in 3 sec spinner