12th Class Physics Magnetism Question Bank MCQ - Moving Charges and Magnetism

  • question_answer
    For the magnetic field to be maximum due to a small element of current carrying conductor at a point, the angle between the element and the line joining the element to the given point must be:

    A) \[0{}^\circ \]      

    B) \[90{}^\circ \]    

    C) \[180{}^\circ \]                        

    D) \[45{}^\circ \]          

    Correct Answer: B

    Solution :

    (b) \[90{}^\circ \]                                           The magnetic field due to small element of current carrying conductor of length l is given by             \[dB=\frac{{{\mu }_{0}}}{4\pi }\frac{idl\,\sin \theta }{{{r}^{2}}}\] This value will be maximum when             \[sin\,\theta =1=sin\,90{}^\circ \Rightarrow \theta =90{}^\circ \]


You need to login to perform this action.
You will be redirected in 3 sec spinner