A) \[2.4\times {{10}^{-4}}T\]
B) \[3.5\times {{10}^{-4}}T\]
C) \[2.79\times {{10}^{-4}}T\]
D) \[3\times {{10}^{-4}}T\]
Correct Answer: C
Solution :
(c) \[2.79\times {{10}^{-4}}T\] Here \[N=100\] \[R=9\,cm=9\times {{10}^{-2}}m\] and \[l=0.4\,A\] Now, \[B=\frac{{{\mu }_{0}}Nl}{2R}=\frac{2\pi \times {{10}^{-7}}\times 100\times 0.4}{9\times {{10}^{-2}}}\] \[=\frac{2\times 3.14\times 0.4}{9}\times {{10}^{-3}}=0.279\times {{10}^{-3}}T\] \[=2.79\times {{10}^{-4}}T\]
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