A) \[0{}^\circ \]
B) \[90{}^\circ \]
C) \[180{}^\circ \]
D) \[45{}^\circ \]
Correct Answer: B
Solution :
(b) \[90{}^\circ \] The magnetic field due to small element of current carrying conductor of length l is given by \[dB=\frac{{{\mu }_{0}}}{4\pi }\frac{idl\,\sin \theta }{{{r}^{2}}}\] This value will be maximum when \[sin\,\theta =1=sin\,90{}^\circ \Rightarrow \theta =90{}^\circ \]You need to login to perform this action.
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