A) \[\frac{1}{r}\]
B) \[\frac{1}{{{r}^{2}}}\]
C) \[\frac{1}{{{r}^{3}}}\]
D) \[\frac{1}{{{r}^{3/2}}}\]
Correct Answer: C
Solution :
(c) \[\frac{1}{{{r}^{3}}}\] \[B=\frac{{{\mu }_{0}}l{{a}^{2}}}{2{{({{a}^{2}}+{{r}^{2}})}^{3/2}}}=\frac{{{\mu }_{0}}l{{a}^{2}}}{2{{r}^{3}}}\,\text{for}\,{{r}^{2}}+{{a}^{2}}\approx {{r}^{2}}\].You need to login to perform this action.
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