A) \[ni(\overrightarrow{A}\times \overrightarrow{B})\]
B) \[ni(\overrightarrow{A}\cdot \overrightarrow{B})\]
C) \[\frac{i(\overrightarrow{A}\times \overrightarrow{B})}{n}\]
D) \[\frac{i(\overrightarrow{A}\cdot \overrightarrow{B})}{n}\]
Correct Answer: A
Solution :
(a) \[ni(\overrightarrow{A}\times \overrightarrow{B})\] \[\overrightarrow{\tau }=\overrightarrow{M}\times \overrightarrow{B}\] \[=ni(\overrightarrow{A}\times \overrightarrow{B})\] \[(\because \,\overrightarrow{M}=ni\,\overrightarrow{A})\]You need to login to perform this action.
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