A) 100
B) 200
C) 300
D) 400
Correct Answer: D
Solution :
(d) 400. Magnetic field, \[B=\frac{{{\mu }_{0}}{{\mu }_{r}}Nl}{2\pi r}\] \[1.0=\frac{4\pi \times {{10}^{-7}}\times {{\mu }_{r}}\times 400\times 2}{40\times {{10}^{-2}}}\] \[\Rightarrow {{\mu }_{r}}\approx 400\].
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