A) \[72.2\text{ }A\,{{m}^{2}}\]
B) \[70.5\text{ }A\,{{m}^{2}}\]
C) \[74.56\text{ }A\,{{m}^{2}}\]
D) \[75.56\text{ }A\,{{m}^{2}}\]
Correct Answer: D
Solution :
(d) \[75.56\text{ }A\,{{m}^{2}}\] Given, \[N=35,\,\,r=25cm=25\times {{10}^{-2}}m,\,l=11A\] Then magnetic moment associated with this circular coil \[M=NlA=Nl\pi {{r}^{2}}=35\times 11\times 3.14\times {{(25\times {{10}^{-2}})}^{2}}\] \[=75.56\,{{m}^{2}}\].
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