\[A\xleftarrow[\Delta ]{Cu}C{{H}_{3}}C{{H}_{2}}OH\xrightarrow[\Delta ]{A{{l}_{2}}{{O}_{2}}}B\] |
A and B respectively are |
A) alkene, alkyne
B) alkanal, alkene
C) alkyne, alkanal
D) alkene, alkanal
Correct Answer: B
Solution :
[b]Ethanol on reduction with Cu gives ethanal which an reaction with \[A{{l}_{2}}{{O}_{3}}\] it reduces to ethene. |
\[\underset{Ethanal}{\mathop{C{{H}_{3}}CHO}}\,\xleftarrow[\Delta ]{Cu}C{{H}_{3}}C{{H}_{2}}OH\xrightarrow[\Delta ]{A{{l}_{2}}{{O}_{3}}}\underset{Ethene}{\mathop{C{{H}_{2}}=C{{H}_{2}}}}\,\] |
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