A) \[C{{H}_{3}}COOH\]
B) \[C{{H}_{3}}CON{{H}_{2}}\]
C) \[{{C}_{6}}{{H}_{5}}OH\]
D) \[C{{H}_{3}}C{{H}_{2}}OH\]
Correct Answer: D
Solution :
\[C{{H}_{3}}COOH\xrightarrow[-{{H}_{2}}O]{NaOH}C{{H}_{3}}COONa\] \[C{{H}_{3}}CON{{H}_{2}}\xrightarrow{NaOH}C{{H}_{3}}COONa+N{{H}_{3}}\] \[{{C}_{6}}{{H}_{5}}OH\xrightarrow{NaOH}{{C}_{6}}{{H}_{5}}ONa+{{H}_{2}}O\] But alcohols are weakly acidic even weaker than water and react with alkali metals to form alkoxides and not with alkali.You need to login to perform this action.
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