A) \[5\sqrt{2}\operatorname{A}\]
B) \[5\sqrt{\frac{3}{2}}\operatorname{A}\]
C) \[\frac{5}{6}\]A
D) \[\frac{5}{\sqrt{2}}\operatorname{A}\]
Correct Answer: B
Solution :
| Option [b] is correct |
| Explanation: Here, \[{{I}_{\operatorname{rms}}}\]=5 A, n 50 Hz and \[t\frac{1}{300}s\] |
| = Peak value =\[\sqrt{2}{{\operatorname{I}}_{rms}}=\sqrt{2}\times 5=5\sqrt{2}\operatorname{A}\] |
| Now, I = \[{{I}_{0}}\ \sin \ \omega t=5\sqrt{2}\ \sin \ 2\pi vt\] |
| \[=5\sqrt{2}\ \sin \ 2\pi \times 50\times \frac{1}{300}=5\sqrt{\frac{3}{2}}A\] |
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