A) 1/\[\sqrt{2}\]A
B) \[\sqrt{2}\] A
C) 2 A
D) 2\[\sqrt{2}\]A
Correct Answer: A
Solution :
| Option [a] is correct |
| Explanation: Given, Power associated with secondary, \[{{P}_{s}}\] = 12 W |
| Secondary voltage, \[{{V}_{s}}\] = 24 V |
| Current in the secondary, \[{{I}_{s}}=\frac{{{P}_{s}}}{{{V}_{s}}}=\frac{12}{24}=0.5\]A |
| Peak value of the current in the secondary, \[{{I}_{0}}={{I}_{s}}\sqrt{2}=(0.5)(1.414)=0.707\ or\ \frac{1}{\sqrt{2}}A\]. |
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