A) \[\pi \]
B) \[\frac{\pi }{2}\]
C) \[2\sqrt{2}\]
D) \[2\]
Correct Answer: D
Solution :
| [d] Diameter of circle = 2 unit |
| \[\therefore \] Diagonal of the square = 2 units |
| Side of the square \[=\frac{2}{\sqrt{2}}=\sqrt{2}\] units |
| \[\therefore \] Area of the square \[={{(\sqrt{2})}^{2}}=2sq.\]units |
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