A) \[1:2\]
B) \[1:3\]
C) \[1:4\]
D) \[1:\sqrt{2}\]
Correct Answer: A
Solution :
| [a] Let side of square = x units |
| Diagonal of the square \[=\sqrt{2}x\] units |
| Diameter of the in circle = x units |
| Diameter of the circumcircle \[=\sqrt{2}x\] units |
| \[\frac{\text{Area of incircle}}{\text{Area of circumcircle}}=\frac{\pi {{\left( \frac{x}{2} \right)}^{2}}}{\pi {{\left( \frac{\sqrt{2}x}{2} \right)}^{2}}}=\frac{1}{2}=1:2\] |
You need to login to perform this action.
You will be redirected in
3 sec
