A) \[50c{{m}^{2}}\]
B) \[62.78\,c{{m}^{2}}\]
C) \[49.88\,c{{m}^{2}}\]
D) \[67.67\,c{{m}^{2}}\]
Correct Answer: D
Solution :
| [d] \[\angle AOB=60{}^\circ \] |
| and \[OA=OB\] (radii) |
| \[\therefore \,\,\Delta AOB\] is an equilateral triangle |
| Area of triangle \[=\frac{\sqrt{3}}{4}\times {{5}^{2}}=\frac{25\sqrt{3}}{4}c{{m}^{2}}\] |
| Area of shaded region |
| \[=\text{Area of circle}-\text{Area of triangle}\] |
| \[=\left( \frac{22}{7}\times 5\times 5-\frac{25\sqrt{3}}{4} \right)c{{m}^{2}}\] |
| \[=67.67c{{m}^{2}}\] |
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