A) \[9:4\]
B) \[4:9\]
C) \[2:3\]
D) \[\text{16}:\text{81}\]
Correct Answer: D
Solution :
| [d] \[\frac{2\pi {{r}_{1}}}{2\pi {{r}_{2}}}=\frac{4}{9}\,\,\,\,\,\,\,\Rightarrow \,\,\,\frac{{{r}_{1}}}{{{r}_{2}}}=\frac{4}{9}\] |
| Now, \[\frac{\pi r_{1}^{2}}{\pi r_{2}^{2}}={{\left( \frac{{{r}_{1}}}{{{r}_{2}}} \right)}^{2}}={{\left( \frac{4}{9} \right)}^{2}}=\frac{16}{81}\] |
| \[\therefore \] Ratio of areas \[=16:81\] |
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