A) \[\pi (2r+h)r\]
B) \[\pi (2r+h)h\]
C) \[\pi (h+r)r\]
D) \[\pi (h+r)h\]
Correct Answer: B
Solution :
[b] Here. radius of inner circle is r and width of path is h. |
\[\therefore \] Radius of outer circle \[=r+h\] |
Now, area of path |
\[=\pi {{(r+h)}^{2}}-\pi {{r}^{2}}=\pi ({{r}^{2}}+{{h}^{2}}+2rh-{{r}^{2}})\] |
\[=\pi (h+2r)h\] |
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