A) \[14.14\,{{m}^{2}}\]
B) \[7.07\,{{m}^{2}}\]
C) \[6.07\,{{m}^{2}}\]
D) None of these
Correct Answer: B
Solution :
| [b] Given, radius of sector \[(r)=3m\] |
| Field is rectangular |
| \[\therefore \] Central angle \[(\theta )=90{}^\circ \] |
| So, required area |
| \[\frac{\theta }{360{}^\circ }\times \pi {{r}^{2}}=\frac{90{}^\circ }{360{}^\circ }\times \frac{22}{7}\times {{(3)}^{2}}\] |
| \[=\frac{99}{14}=7.07{{m}^{2}}\] |
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