In fig., OAB is a sector of circle of radius\[\text{1}0.\text{5}~~\text{cm}\].The perimeter or Circumference of the sector is \[\left( Take\,\,\pi =\frac{22}{7} \right)\] (CBSE 2020) |
A) \[30\,cm\]
B) \[32\,cm\]
C) \[34\,cm\]
D) \[36\,cm\]
Correct Answer: B
Solution :
[b] Given, radius of the circle \[(r)=10.5\,cm\] |
\[\therefore \] Perimeter of sector \[=OA+OB+\overset{\cap }{\mathop{AB}}\,\] |
\[=r+r+\] length of arc AB |
\[=10.5+10.5+\frac{60{}^\circ }{360{}^\circ }\times 2\times \frac{22}{7}\times 10.5\] |
\[=21+\frac{22\times 1.5}{3}=21+11=32cm\] |
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