A) \[\frac{77}{2}{{m}^{2}}\]
B) \[77\,{{m}^{2}}\]
C) \[\frac{77}{8}\,{{m}^{2}}\]
D) \[\frac{77}{4}\,{{m}^{2}}\]
Correct Answer: C
Solution :
| [c] Diameter of circle \[=3.5m\] |
| \[\therefore \] Radius of circle \[=\frac{3.5}{2}m\] |
| then area of circle |
| \[=\pi \times {{\left( \frac{3.5}{2} \right)}^{2}}=\frac{22}{7}\times \frac{3.5}{2}\times \frac{3.5}{2}=\frac{77}{8}{{m}^{2}}\] |
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