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12th Class Physics Atomic Physics Question Bank MCQs - Atoms

  • question_answer
    Two H atoms in the ground state collide inelastically. The maximum amount by which their combined kinetic energy is reduced, is

    A) 10.20 eV

    B) 20.40 eV

    C) 13.6 eV

    D) 27.2 eV

    Correct Answer: A

    Solution :

    Option [a] is correct.
    Explanation: Total energy of two H-atom in ground state = 2(-13.6) = -27.2 eV.
    The maximum amount by which their combined kinetic energy is reduced when any one H-atom goes into first excited state after the inelastic collision, that is, the total energy of two H-atom after inelastic collision:
    \[\operatorname{E}=\frac{13.6}{{{n}^{2}}}+13.6\]
    \[=\frac{13.6}{{{2}^{2}}}+13.61\] [For excited state (n = 2)]
    = 3.4+13.6 = 17.0 eV                    
    So that the loss in kinetic energy due to inelastic collision will be,
    = 27.2 -17.0 = 10.2 eV


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