A) right triangle
B) isosceles triangle
C) equilateral triangle
D) scalene triangle
Correct Answer: B
Solution :
[b] Let \[A(-4,0),\] \[B(4,0),\] \[C(0,3)\]are the given vertices. |
Now, distance between \[A(-4,0)\] and \[B(4,0)\] |
\[AB=\sqrt{{{[4-(-4)]}^{2}}+{{(0-0)}^{2}}}=\sqrt{{{(4+4)}^{2}}}=\sqrt{{{8}^{2}}}=8\]Distance between \[B(4,0)\] and \[C(0,3)\] |
\[BC=\sqrt{{{(0-4)}^{2}}+{{(3-0)}^{2}}}=\sqrt{16+9}=\sqrt{25}=5\] |
Distance between \[A(-4,0)\] and \[C(0,3)\]. |
\[AC=\sqrt{[0-{{(-4)}^{2}}]+{{(3-0)}^{2}}}=\sqrt{16+9}=\sqrt{25}=5\] \[BC=AC\] |
Hence, \[\Delta ABC\] is an isosceles triangle because an isosceles triangle has two sides equal. |
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