A) \[ac-bd=0\]
B) \[ac+bd=0\]
C) \[ab+cd=0\]
D) \[ab-cd=0\]
Correct Answer: B
Solution :
[b] Let \[A(a,b),\,\,\,B(c,d),\,\,O(0,0)\] |
\[\therefore \,\,\,\,\angle AOB=90{}^\circ \,\,\,\,\Rightarrow \,\,\,A{{B}^{2}}=A{{O}^{2}}+B{{O}^{2}}\] |
\[\therefore \,\,\,{{(c-a)}^{2}}+{{(d-b)}^{2}}={{a}^{2}}+{{b}^{2}}+{{c}^{2}}+{{d}^{2}}\] |
\[\Rightarrow \,\,\,\,\,\,\,ac+bd=0\] |
You need to login to perform this action.
You will be redirected in
3 sec