A) 3
B) \[-3\]
C) 7
D) 4
Correct Answer: A
Solution :
[a] We know that, mid-point of the diameter of the circle is centre of the circle. |
\[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(3,5)=\left\{ \frac{4+2}{2},\frac{7+y}{2} \right\}\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(3,5)=\left\{ 3,\frac{7+y}{2} \right\}\] |
On comparing, we get |
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