In figure \[P(5,-3)\] and \[Q(3,y)\] are the points of Insertion of the line segment joining \[A(7,-2)\] and \[B(1,-5),\] then y equals: (CBSE 2012) |
A) \[2\]
B) \[4\]
C) \[-4\]
D) \[-\frac{5}{2}\]
Correct Answer: C
Solution :
[c] |
\[AP=PQ=BQ\] |
\[\Rightarrow \] Q is mid-point of PB |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,y=\frac{-3+(-5)}{2}=-4\] |
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